Integrand size = 22, antiderivative size = 242 \[ \int \frac {\sqrt {c+a^2 c x^2} \arctan (a x)}{x^2} \, dx=-\frac {\sqrt {c+a^2 c x^2} \arctan (a x)}{x}-\frac {2 i a c \sqrt {1+a^2 x^2} \arctan (a x) \arctan \left (\frac {\sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}-a \sqrt {c} \text {arctanh}\left (\frac {\sqrt {c+a^2 c x^2}}{\sqrt {c}}\right )+\frac {i a c \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (2,-\frac {i \sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}-\frac {i a c \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (2,\frac {i \sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}} \]
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Time = 0.17 (sec) , antiderivative size = 242, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.318, Rules used = {5070, 5064, 272, 65, 214, 5010, 5006} \[ \int \frac {\sqrt {c+a^2 c x^2} \arctan (a x)}{x^2} \, dx=-\frac {2 i a c \sqrt {a^2 x^2+1} \arctan \left (\frac {\sqrt {1+i a x}}{\sqrt {1-i a x}}\right ) \arctan (a x)}{\sqrt {a^2 c x^2+c}}-\frac {\arctan (a x) \sqrt {a^2 c x^2+c}}{x}-a \sqrt {c} \text {arctanh}\left (\frac {\sqrt {a^2 c x^2+c}}{\sqrt {c}}\right )+\frac {i a c \sqrt {a^2 x^2+1} \operatorname {PolyLog}\left (2,-\frac {i \sqrt {i a x+1}}{\sqrt {1-i a x}}\right )}{\sqrt {a^2 c x^2+c}}-\frac {i a c \sqrt {a^2 x^2+1} \operatorname {PolyLog}\left (2,\frac {i \sqrt {i a x+1}}{\sqrt {1-i a x}}\right )}{\sqrt {a^2 c x^2+c}} \]
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Rule 65
Rule 214
Rule 272
Rule 5006
Rule 5010
Rule 5064
Rule 5070
Rubi steps \begin{align*} \text {integral}& = c \int \frac {\arctan (a x)}{x^2 \sqrt {c+a^2 c x^2}} \, dx+\left (a^2 c\right ) \int \frac {\arctan (a x)}{\sqrt {c+a^2 c x^2}} \, dx \\ & = -\frac {\sqrt {c+a^2 c x^2} \arctan (a x)}{x}+(a c) \int \frac {1}{x \sqrt {c+a^2 c x^2}} \, dx+\frac {\left (a^2 c \sqrt {1+a^2 x^2}\right ) \int \frac {\arctan (a x)}{\sqrt {1+a^2 x^2}} \, dx}{\sqrt {c+a^2 c x^2}} \\ & = -\frac {\sqrt {c+a^2 c x^2} \arctan (a x)}{x}-\frac {2 i a c \sqrt {1+a^2 x^2} \arctan (a x) \arctan \left (\frac {\sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}+\frac {i a c \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (2,-\frac {i \sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}-\frac {i a c \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (2,\frac {i \sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}+\frac {1}{2} (a c) \text {Subst}\left (\int \frac {1}{x \sqrt {c+a^2 c x}} \, dx,x,x^2\right ) \\ & = -\frac {\sqrt {c+a^2 c x^2} \arctan (a x)}{x}-\frac {2 i a c \sqrt {1+a^2 x^2} \arctan (a x) \arctan \left (\frac {\sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}+\frac {i a c \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (2,-\frac {i \sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}-\frac {i a c \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (2,\frac {i \sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}+\frac {\text {Subst}\left (\int \frac {1}{-\frac {1}{a^2}+\frac {x^2}{a^2 c}} \, dx,x,\sqrt {c+a^2 c x^2}\right )}{a} \\ & = -\frac {\sqrt {c+a^2 c x^2} \arctan (a x)}{x}-\frac {2 i a c \sqrt {1+a^2 x^2} \arctan (a x) \arctan \left (\frac {\sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}-a \sqrt {c} \text {arctanh}\left (\frac {\sqrt {c+a^2 c x^2}}{\sqrt {c}}\right )+\frac {i a c \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (2,-\frac {i \sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}}-\frac {i a c \sqrt {1+a^2 x^2} \operatorname {PolyLog}\left (2,\frac {i \sqrt {1+i a x}}{\sqrt {1-i a x}}\right )}{\sqrt {c+a^2 c x^2}} \\ \end{align*}
Time = 0.49 (sec) , antiderivative size = 163, normalized size of antiderivative = 0.67 \[ \int \frac {\sqrt {c+a^2 c x^2} \arctan (a x)}{x^2} \, dx=-\frac {a \sqrt {c \left (1+a^2 x^2\right )} \left (\frac {\sqrt {1+a^2 x^2} \arctan (a x)}{a x}-\arctan (a x) \log \left (1-i e^{i \arctan (a x)}\right )+\arctan (a x) \log \left (1+i e^{i \arctan (a x)}\right )+\log \left (\cos \left (\frac {1}{2} \arctan (a x)\right )\right )-\log \left (\sin \left (\frac {1}{2} \arctan (a x)\right )\right )-i \operatorname {PolyLog}\left (2,-i e^{i \arctan (a x)}\right )+i \operatorname {PolyLog}\left (2,i e^{i \arctan (a x)}\right )\right )}{\sqrt {1+a^2 x^2}} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 929 vs. \(2 (199 ) = 398\).
Time = 0.60 (sec) , antiderivative size = 930, normalized size of antiderivative = 3.84
method | result | size |
default | \(\frac {\ln \left (\frac {i a x +1}{\sqrt {a^{2} x^{2}+1}}-1\right ) \left (i a^{2} x^{2}+2 a x -i\right ) \sqrt {c \left (a x -i\right ) \left (a x +i\right )}}{4 \sqrt {a^{2} x^{2}+1}\, x}-\frac {\ln \left (\frac {i a x +1}{\sqrt {a^{2} x^{2}+1}}+1\right ) \left (i a^{2} x^{2}+2 a x -i\right ) \sqrt {c \left (a x -i\right ) \left (a x +i\right )}}{4 \sqrt {a^{2} x^{2}+1}\, x}+\frac {\operatorname {dilog}\left (1-\frac {i \left (i a x +1\right )}{\sqrt {a^{2} x^{2}+1}}\right ) \left (a^{2} x^{2}-2 i a x -1\right ) \sqrt {c \left (a x -i\right ) \left (a x +i\right )}}{4 \sqrt {a^{2} x^{2}+1}\, x}-\frac {\arctan \left (a x \right ) \ln \left (1+\frac {i \left (i a x +1\right )}{\sqrt {a^{2} x^{2}+1}}\right ) \left (i a^{2} x^{2}+2 a x -i\right ) \sqrt {c \left (a x -i\right ) \left (a x +i\right )}}{4 \sqrt {a^{2} x^{2}+1}\, x}+\frac {\arctan \left (a x \right ) \ln \left (1-\frac {i \left (i a x +1\right )}{\sqrt {a^{2} x^{2}+1}}\right ) \left (i a^{2} x^{2}+2 a x -i\right ) \sqrt {c \left (a x -i\right ) \left (a x +i\right )}}{4 \sqrt {a^{2} x^{2}+1}\, x}-\frac {\operatorname {dilog}\left (1+\frac {i \left (i a x +1\right )}{\sqrt {a^{2} x^{2}+1}}\right ) \left (a^{2} x^{2}-2 i a x -1\right ) \sqrt {c \left (a x -i\right ) \left (a x +i\right )}}{4 \sqrt {a^{2} x^{2}+1}\, x}+\frac {\sqrt {c \left (a x -i\right ) \left (a x +i\right )}\, \left (a^{2} x^{2}+2 i a x -1\right ) \operatorname {dilog}\left (1+\frac {i \left (i a x +1\right )}{\sqrt {a^{2} x^{2}+1}}\right )}{4 \sqrt {a^{2} x^{2}+1}\, x}+\frac {\sqrt {c \left (a x -i\right ) \left (a x +i\right )}\, \left (i a^{2} x^{2}-2 a x -i\right ) \ln \left (1+\frac {i \left (i a x +1\right )}{\sqrt {a^{2} x^{2}+1}}\right ) \arctan \left (a x \right )}{4 \sqrt {a^{2} x^{2}+1}\, x}-\frac {\sqrt {c \left (a x -i\right ) \left (a x +i\right )}\, \left (i a^{2} x^{2}-2 a x -i\right ) \ln \left (1-\frac {i \left (i a x +1\right )}{\sqrt {a^{2} x^{2}+1}}\right ) \arctan \left (a x \right )}{4 \sqrt {a^{2} x^{2}+1}\, x}-\frac {\sqrt {c \left (a x -i\right ) \left (a x +i\right )}\, \left (a^{2} x^{2}+2 i a x -1\right ) \operatorname {dilog}\left (1-\frac {i \left (i a x +1\right )}{\sqrt {a^{2} x^{2}+1}}\right )}{4 \sqrt {a^{2} x^{2}+1}\, x}-\frac {\arctan \left (a x \right ) \left (i a x +1\right ) \sqrt {c \left (a x -i\right ) \left (a x +i\right )}}{2 x}-\frac {\sqrt {c \left (a x -i\right ) \left (a x +i\right )}\, \left (i a^{2} x^{2}-2 a x -i\right ) \ln \left (\frac {i a x +1}{\sqrt {a^{2} x^{2}+1}}-1\right )}{4 \sqrt {a^{2} x^{2}+1}\, x}+\frac {\sqrt {c \left (a x -i\right ) \left (a x +i\right )}\, \left (i a^{2} x^{2}-2 a x -i\right ) \ln \left (\frac {i a x +1}{\sqrt {a^{2} x^{2}+1}}+1\right )}{4 \sqrt {a^{2} x^{2}+1}\, x}+\frac {\sqrt {c \left (a x -i\right ) \left (a x +i\right )}\, \left (i a x -1\right ) \arctan \left (a x \right )}{2 x}\) | \(930\) |
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\[ \int \frac {\sqrt {c+a^2 c x^2} \arctan (a x)}{x^2} \, dx=\int { \frac {\sqrt {a^{2} c x^{2} + c} \arctan \left (a x\right )}{x^{2}} \,d x } \]
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\[ \int \frac {\sqrt {c+a^2 c x^2} \arctan (a x)}{x^2} \, dx=\int \frac {\sqrt {c \left (a^{2} x^{2} + 1\right )} \operatorname {atan}{\left (a x \right )}}{x^{2}}\, dx \]
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\[ \int \frac {\sqrt {c+a^2 c x^2} \arctan (a x)}{x^2} \, dx=\int { \frac {\sqrt {a^{2} c x^{2} + c} \arctan \left (a x\right )}{x^{2}} \,d x } \]
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Exception generated. \[ \int \frac {\sqrt {c+a^2 c x^2} \arctan (a x)}{x^2} \, dx=\text {Exception raised: TypeError} \]
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Timed out. \[ \int \frac {\sqrt {c+a^2 c x^2} \arctan (a x)}{x^2} \, dx=\int \frac {\mathrm {atan}\left (a\,x\right )\,\sqrt {c\,a^2\,x^2+c}}{x^2} \,d x \]
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